How to escape (percent-encode) a URL with Python
import urllib
print urllib.quote_plus("http://www.yahoo.com/")
print urllib.quote_plus("Kruder & Dorfmeister")
Results:
http%3A%2F%2Fwww.yahoo.com%2F Kruder+%26+Dorfmeister
It is easy to be drawn to the urlencode function
in the Python
urllib module documentation. But for simple
escaping, only quote_plus, or possibly quote
is needed. I believe this is the appropriate solution to
Python urlencode annoyance and
O'Reilly's Amazon Hack #92.
For reference: Percent-encoding on Wikipedia
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#1 xav commented on 2009-02-25:
Nice music exemple :)